A six-faced fair dice is rolled five times. The probability (in %) of obtaining “ONE” at least four times is
- 33.3
- 3.33
- 0.33
- 0.0033
Answer (Detailed Solution Below)
Option 3 : 0.33
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CT 1: Ratio and Proportion
10 Questions 16 Marks 30 Mins
Concept:
The binomial probability formula:
Probability of r successes in n trials:
P(r) = nCrprqn-r
n = number of trials, r = number of success in n trials
p = probability of success in any one trial, q = probability of failure in any one trial = 1 – p
Calculation:
Probability of getting “ONE” in one throw:
p = 1/6
Probability of NOT getting “ONE” in one throw:
q = 1 – p = 5/6
Probability of obtaining “ONE” at least four times in five throws:
r ≥ 4 i.e. r = 4 and r = 5
P (r ≥ 4) = P (r = 4) + P (r = 5) = 5C4p4q1 + 5C5p5q0
\(P\left( {r \ge 4} \right) = 5 \times {\left( {\frac{1}{6}} \right)^4}\left( {\frac{5}{6}} \right) + 1{\left( {\frac{1}{6}} \right)^5} = {\left( {\frac{1}{6}} \right)^5}\left( {25 + 1} \right) = 26 \times {\left( {\frac{1}{6}} \right)^5} = 0.0033 = 0.33\% \)
Mistake: Probability is asked in %age to don’t forget to convert it in %age.
Last updated on Dec 15, 2022
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A single fair die is tossed. Find the probability of {rolling number greater than 5. What is the probability of rolling a number greater than 5? (Simplify your answer Type a fraction )
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Video Transcript
A single fare diocese was thrown to find out the probability of rolling a number greater than five. The total possible outcome of rolling is one, two, five and six. So the total possible outcome is six. Sex is the only number greater than five that's possible. The number of possible outcomes is equal to the number of rolling numbers greater than five. The number of outcomes is divided by the number of possible outcomes. The required probability is equal to 1 x 6.
웹의 추천 스니펫
Two (6-sided) dice roll probability table
| 2 | 1/36 (2.778%) |
| 3 | 3/36 (8.333%) |
| 4 | 6/36 (16.667%) |
| 5 | 10/36 (27.778%) |
7행 더 보기
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