In what time will the interest on a certain sum of money at 6.25 be 5/8 of itself

(i) Here,

I = Rs 2356.25

R =7 \frac{1}{4} \% \text { p.a }

= 29 / 4 % p.a.

T = 2 \frac{1}{2} \text { years }

= 5 / 2 years

Hence,

P = (I × 100) / (R × T)

= Rs (2356.25 × 100) / (29 / 4) × (5 / 2)

On further calculation, we get,

= Rs (2356.25 × 100 × 4 × 2) / (29 × 5)

= Rs (235625 × 8) / (29 × 5)

We get,

= Rs (47125 × 8) / 29

= Rs 1625 × 8

= Rs 13000

(ii) Amount (A) = Rs 11300

Rate (R) = 4% p.a.

Time (T) = 3 years 3 months

=3 \frac{3}{12} \text { years }

=\frac{3}{4} \text { years }

= 13 / 4 years

Let the principal be Rs x

Hence,

S.I. = (P × R × T) / 100

= Rs (x × 4 × 13) / (100 × 4)

We get,

= Rs 13x / 100

Then,

Amount = Principal + Simple Interest

= Rs x + Rs 13x / 100

= Rs (x + 13x) / 100

We get,

= Rs (100x + 13x) / 100

= Rs (113x / 100)

But, the amount given is Rs 11300

Hence,

113x / 100 = 11300

x = 11300 × 100 / 113

x = 100 × 100

We get,

x = 10000

Therefore, principal (P) = Rs 10000

A sum of money becomes 137.5% of itself in 6 years at a certain rate of interest. Then what will be rate of interest?

  1. 12.25%
  2. 6.25%
  3. 7.25%
  4. 11.25%

Answer (Detailed Solution Below)

Option 2 : 6.25%

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10 Questions 10 Marks 7 Mins

Given:

In 6 years a sum becomes 137.5% of itself

Formula used:

S. I. = (P × t × r)/100

S. I = Simple Interest

P = principal

t = Time period

r = Rate of interest

Calculation:

Let P is the original amount. 

After 6 years, it becomes 137.5% of P.

⇒ New amount = (137.5/100)P = 11/8P

⇒ Inntrest = 11P/8 - P = 3P/8

Now using the above formula, let the rate of interest be R.

⇒ 3P/8 = (P × 6 × R)/100

⇒ 1/8 = R/50

∴  R = 6.25 %

Alternate MethodLet the P be 8x

137.5% = 11/8

8x × 11/8 = 11x

According to the question,

Interest = 11x – 8x = 3x

3x = (8x × 6 × r)/100

⇒ 300x = 48xr

⇒ 25 = 4r

⇒ 25/4 = r

⇒ r = 6.25

⇒ Rate of interest = 6.25%

∴ The rate of interest is 6.25%

Alternate Method

In 6 years 8P becomes 11P

Interest =  11P –  8P = 3P 

3P in 6 years

⇒ 0.5P in 1 year

Rate % = (0.5P/8P) × 100

⇒ 0.0625 × 100

⇒ 6.25%

⇒ Rate of interest = 6.25%

∴ The rate of interest is 6.25%

Last updated on Sep 21, 2022

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The compound interest on a sum of money at 5% per annum for a period of 2 years is ₹ 6560. What will be the simple interest on the same sum for the same period at the same rate?

  1. ₹ 6400 
  2. ₹ 6440
  3. ₹ 6260 
  4. ₹ 6380

Answer (Detailed Solution Below)

Option 1 : ₹ 6400 

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12 Questions 15 Marks 10 Mins

Given:

Time = 2 years

Rate, R = 5% per annum

CI = ₹ 6560

Concept:

  • \(CI= P[(1+\frac{R}{100})^n-1]\)
  • SI = (PRT)/100

Calculation:

We know that,

\(CI= P[(1+\frac{R}{100})^n-1]\)

\(⇒ 6560= P[(1 + \frac{5}{100})^2-1]\)

⇒ 6560 = P[(21/20)2 - 1]

⇒ 6560 = P[(441/400) - 1] 

⇒ 6560 = P(41/400)

⇒ P = 64000

Now, SI = (64000 × 5 × 2)/100

⇒ SI = 6400

Hence, the simple interest is ₹ 6400.

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What time will the interest on a certain sum of money at 6% be 5/8 of itself?

question_answer Answers(3) Given that sum of money at 6% be 5/8 of itself. Therefore, S.I = 5x / 8. T = (S.I × 100) / P × R. That is 10 years and 5 months.

In what time will the interest on a certain sum of money at 7% be 11/4 of itself?

Therefore the time of investment is 25 years.

In what time will a sum of money double itself at 5 pa simple interest?

Answer. time = si × 100 / R × P 100× 100 / 5 × 100 = 20 years .

In what time will a sum of money double itself at?

In how many years will a sum of money double itself with the rate of 10% per annum simple interest? Here, we have R = 10% and have to calculate t for the sum of the money (that is P) to double. Hence, it will take 10 years for the sum of money to double itself with the rate of 10% per annum simple interest.

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