A sum of money at simple interest triples itself in 15 years it will become 5 times of itself in

A sum of money triples itself in \[15\] years \[6\] months. In how many years would it double itself?A. \[6\] years \[3\] monthsB. \[7\] years \[9\] monthsC. \[8\] years \[3\] monthsD. \[9\] years \[6\] months

Answer

A sum of money at simple interest triples itself in 15 years it will become 5 times of itself in
Verified

Hint: To solve this question, we need to apply the basic formula of simple interest which is \[S.I. = \dfrac{{PTR}}{{100}}\] . In the question, we are given the time, so first we calculate the rate using principal amount and simple interest and then use this calculated rate to solve time for the second part.

Complete step-by-step answer:
In the question, it is given that a sum of money triples itself in \[15\] years \[6\] months
Therefore, let the sum be \[x\] then, simple interest \[S.I.\] will be \[2x\] .
Time required to triple the money is given as \[15\] years \[6\] months \[ = 15\dfrac{1}{2} = \dfrac{{31}}{2}\] years
Now, Simple Interest \[S.I. = \dfrac{{PTR}}{{100}}\]
Putting the values in above formula of simple interest, we get
\[2x = \dfrac{{x.\dfrac{{31}}{2}.R}}{{100}}\]
Or, \[R = \dfrac{{400}}{{31}}\% \]
Now, to calculate in how many years it becomes double,
So, it will now give \[x\] interest on the sum of \[x\] .
So, sum be \[x\] then, simple interest \[S.I.\] will be \[x\] .
Now, Simple Interest \[S.I. = \dfrac{{PTR}}{{100}}\]
Putting the values in above formula of simple interest, we get
\[x = \dfrac{{x.T.\dfrac{{400}}{{31}}}}{{100}}\]
Or, \[T = \dfrac{{31}}{4}\]
\[T = 7\dfrac{3}{4}\] years
Or, the time it takes to double is \[7\] years \[9\] months.

So, the correct answer is “Option B”.

Note: Remember the formula of simple interest. Simple interest is calculated by multiplying the interest rate by the principal amount and the time period which is generally in years. The \[S.I.\] formula is given as: \[S.I. = \dfrac{{PTR}}{{100}}\]

Solution

The formula for simple interest calculation is - I = P*R*T/100Where I is interestP is principal amountR is rate of interestT is time in Years.Now you want to triple the money. That means I = 2PHence 2P = P*R*T/1002*100 = 15*THence T = 200/15 = 13.33Y or 13Y and 4 months.So the answer for your question is 13Y and 4 months.

A sum of money at simple interest triples itself in 15 years it will become 5 times of itself in
A sum of money at simple interest triples itself in 15 years it will become 5 times of itself in
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A sum of money at simple interest triples itself in 15 years it will become 5 times of itself in


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  1. A sum of money at simple interest trebles itself in 15 years. It will become 5 times of itself in

    1. 40 years
    2. 36 years
    3. 30 years
    4. 25 years

Correct Option: C

Let the principal be P.
Case-I

2P = P × R × 15
100

⇒ 2P = 2 × 100 = 40 %
15 3

Case-II
SI = 4P

∴ 4P = P × 40 × T
100

⇒ T= 4 × 300 = 30 yaers
40

Second method to solve this question :

R = (3 - 1) × 100%
15

R = 2 × 100% = 2 × 20%
15 15

R = 40 %
3

T = (n - 1) Years
R

T = (5 - 1) × 100
(40 ÷ 3)

T = 30 years.

A sum of money at simple interest triples itself in 15 years it will become 5 times of itself in


Your comments will be displayed only after manual approval.

In what time will a sum of money put at 15 simple interest triples itself?

So the answer for your question is 13Y and 4 months.

At what rate percent per annum simple interest will a sum triple itself in 15 years?

⇒R=2P×100P×16=12.5%

In what time a sum of money triples itself at 5%?

Given: The sum of money triples itself. ∴ The number of years by which a sum will triple itself at 5% p.a is 40 years.

What is the rate of interest if a sum of money triples itself in 16 years?

⇒R=162×100=12. 5%