How much will ₹ 5000 amount in 2 years at compound interest if the rate for the successive years are 5% and 4% per year?

Compound Interest: The future value (FV) of an investment of present value (PV) dollars earning interest at an annual rate of r compounded m times per year for a period of t years is:

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FV = PV(1 + r/m)mtor

FV = PV(1 + i)n

where i = r/m is the interest per compounding period and n = mt is the number of compounding periods.

One may solve for the present value PV to obtain:

PV = FV/(1 + r/m)mt

Numerical Example: For 4-year investment of $20,000 earning 8.5% per year, with interest re-invested each month, the future value is

FV = PV(1 + r/m)mt   = 20,000(1 + 0.085/12)(12)(4)   = $28,065.30

Notice that the interest earned is $28,065.30 - $20,000 = $8,065.30 -- considerably more than the corresponding simple interest.

Effective Interest Rate: If money is invested at an annual rate r, compounded m times per year, the effective interest rate is:

reff = (1 + r/m)m - 1.

This is the interest rate that would give the same yield if compounded only once per year. In this context r is also called the nominal rate, and is often denoted as rnom.

Numerical Example: A CD paying 9.8% compounded monthly has a nominal rate of rnom = 0.098, and an effective rate of:

r eff =(1 + rnom /m)m   =   (1 + 0.098/12)12 - 1   =  0.1025.

Thus, we get an effective interest rate of 10.25%, since the compounding makes the CD paying 9.8% compounded monthly really pay 10.25% interest over the course of the year.

Mortgage Payments Components: Let where P = principal, r = interest rate per period, n = number of periods, k = number of payments, R = monthly payment, and D = debt balance after K payments, then

R = P r / [1 - (1 + r)-n]

and

D = P (1 + r)k - R [(1 + r)k - 1)/r]

Accelerating Mortgage Payments Components: Suppose one decides to pay more than the monthly payment, the question is how many months will it take until the mortgage is paid off? The answer is, the rounded-up, where:

n = log[x / (x � P r)] / log (1 + r)

where Log is the logarithm in any base, say 10, or e.

Future Value (FV) of an Annuity Components: Ler where R = payment, r = rate of interest, and n = number of payments, then

FV = [ R(1 + r)n - 1 ] / r

Future Value for an Increasing Annuity: It is an increasing annuity is an investment that is earning interest, and into which regular payments of a fixed amount are made. Suppose one makes a payment of R at the end of each compounding period into an investment with a present value of PV, paying interest at an annual rate of r compounded m times per year, then the future value after t years will be

FV = PV(1 + i)n + [ R ( (1 + i)n - 1 ) ] / i where i = r/m is the interest paid each period and n = m t is the total number of periods.

Numerical Example: You deposit $100 per month into an account that now contains $5,000 and earns 5% interest per year compounded monthly. After 10 years, the amount of money in the account is:

FV = PV(1 + i)n + [ R(1 + i)n - 1 ] / i =
5,000(1+0.05/12)120 + [100(1+0.05/12)120 - 1 ] / (0.05/12) = $23,763.28

Value of a Bond:

V is the sum of the value of the dividends and the final payment.

You may like to perform some sensitivity analysis for the "what-if" scenarios by entering different numerical value(s), to make your "good" strategic decision.

Replace the existing numerical example, with your own case-information, and then click one the Calculate.

hello HD band Assamese calculate the amount and the compound interest on rupees 5000 in two years if the rate of interest for the successive years be eat % and 10% respectively the solution in the want to calculate the amount and the compound interest on rupees 5000 at means principal is equal to rupees 5000 to hear and rate of interest is on the first year it is 8% per annum and second year it is 10% formula for finding amount equal to

is equal to P bracket 1 + 1 upon 101 plus auto upon hundred Patang values wicket is equal to hear it is 5000 RS 5000 oneplus rate of interest for the first year is 8% and rate of interest for the second year is 10% after solving this week 5000 naked 108 108 close and second bracket 110 upon hundred call 2002 108 102 110/100 after serving this

cricket is equal to rupees 5940 we know that compound interest is equal to amount - principal amount is rupees 5940 and principal money is rupees 5000 compound interest is equal to rupees 942

Question

Find the compound interest for 3 years on Rs 5000, if the rate of interest for the successive years are 8%, 6% and 10% respectively.

Hint:

Find the total amount for 3 successive years then subtract the principal amount from it.

The correct answer is: 1296.4 Rupees


    Complete step by step solution:Given that principal amount P = 5000Number of years T = 3Let R1 = 8%,R2 = 6% and R3 = 10%Total amount ,  …(i)On substituting the known values in (i), we get We know that, Compound interest ( CI) = total amount (A) - principal amount (P)So, Compound interest ( CI) = 6296.4 - 5000 = 1296.4 Rupees

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    How much will ₹ 5000 amount in 2 years at compound interest if the rate for the successive years are 5% and 4% per year?
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    How much will ₹ 5000 amount in 2 years at compound interest if the rate for the successive years are 5% and 4% per year?

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    Maths-

    What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

    Complete step by step solution:
    Let the principal amount P = 1092
    It is given that T = 2, R = 12%
    We have the formula for annual payment …(i)
    On substituting the known values in (i), we get

    So, 325 Rupees is the annual instalment.

    What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

    Maths-General

    Complete step by step solution:
    Let the principal amount P = 1092
    It is given that T = 2, R = 12%
    We have the formula for annual payment …(i)
    On substituting the known values in (i), we get

    So, 325 Rupees is the annual instalment.

    Maths-

    What sum of money lent out at 6% for 2 years will produce the same interest as Rs. 1200 lent out at 5% for 3 years.

    Complete step by step solution:
    We calculate simple interest by the formula, …(i)
    where P is Principal amount, T is number of years and R is rate of interest
    Case Ⅰ
    Let the sum of money = P
    Here, we have 
    On substituting the values in (i), we get …(ii)
    Case Ⅱ
    Here, we have 
    On substituting the values in (i), we get …(iii)
    It is given that the interest produced in both the cases is the same.
    So, Equate (ii) and (iii)

    On equating, we get 

     rupees.
    Hence the sum of money P = 1500 Rupees

    What sum of money lent out at 6% for 2 years will produce the same interest as Rs. 1200 lent out at 5% for 3 years.

    Maths-General

    Complete step by step solution:
    We calculate simple interest by the formula, …(i)
    where P is Principal amount, T is number of years and R is rate of interest
    Case Ⅰ
    Let the sum of money = P
    Here, we have 
    On substituting the values in (i), we get …(ii)
    Case Ⅱ
    Here, we have 
    On substituting the values in (i), we get …(iii)
    It is given that the interest produced in both the cases is the same.
    So, Equate (ii) and (iii)

    On equating, we get 

     rupees.
    Hence the sum of money P = 1500 Rupees

    Maths-

    What sum of money lent out at 5% for 3 years will produce the same interest as Rs. 900 lent out at 4% for 5 years.

    Complete step by step solution:
    We calculate simple interest by the formula, …(i)
    where P is Principal amount, T is number of years and R is rate of interest
    Case Ⅰ
    Let the sum of money = P
    Here, we have 
    On substituting the values in (i), we get …(ii)
    Case Ⅱ
    Here, we have 
    On substituting the values in (i), we get …(iii)
    It is given that the interest produced in both the cases is the same.
    So, Equate (ii) and (iii)
    On equating, we get

    rupees.
    Hence the sum of money P = 1200 Rupees

    What sum of money lent out at 5% for 3 years will produce the same interest as Rs. 900 lent out at 4% for 5 years.

    Maths-General

    Complete step by step solution:
    We calculate simple interest by the formula, …(i)
    where P is Principal amount, T is number of years and R is rate of interest
    Case Ⅰ
    Let the sum of money = P
    Here, we have 
    On substituting the values in (i), we get …(ii)
    Case Ⅱ
    Here, we have 
    On substituting the values in (i), we get …(iii)
    It is given that the interest produced in both the cases is the same.
    So, Equate (ii) and (iii)
    On equating, we get

    rupees.
    Hence the sum of money P = 1200 Rupees

    Maths-

    Find the sum which will amount to Rs. 364.80 at 3 % per annum in 8 years at simple interest

    Complete step by step solution:
    Let the sum of money = P
    We know the formula for total amount = A = P + SI
    where A is the total amount, T is the principal amount and R is simple interest.
    We know that 
    where P is Principal amount, T is number of years and R is rate of interest
    So, …(i)
    Here, we have 
    On substituting these values in (i), we get 
    On further simplifications, we get

    Hence the sum of money P = Rs 285.

    Find the sum which will amount to Rs. 364.80 at 3 % per annum in 8 years at simple interest

    Maths-General

    Complete step by step solution:
    Let the sum of money = P
    We know the formula for total amount = A = P + SI
    where A is the total amount, T is the principal amount and R is simple interest.
    We know that 
    where P is Principal amount, T is number of years and R is rate of interest
    So, …(i)
    Here, we have 
    On substituting these values in (i), we get 
    On further simplifications, we get

    Hence the sum of money P = Rs 285.

    Maths-

    The simple interest on a sum of money at the end of 3 years is of the sum itself. What rate percent was charged?

    Complete step by step solution:
    Let the sum of money = P
    It is given that SI is  times the sum itself = P.
    We calculate simple interest by the formula, 
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have 
    On substituting the known values we get, 
    On further simplifications, we have .

    The simple interest on a sum of money at the end of 3 years is of the sum itself. What rate percent was charged?

    Maths-General

    Complete step by step solution:
    Let the sum of money = P
    It is given that SI is  times the sum itself = P.
    We calculate simple interest by the formula, 
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have 
    On substituting the known values we get, 
    On further simplifications, we have .

    Maths-

    A theatre company uses the revenue function  dollars. The cost functions of the production . What ticket price is needed for the theatre to break even?

    A theatre company uses the revenue function  dollars. The cost functions of the production . What ticket price is needed for the theatre to break even?

    Maths-

    Rewrite the equation as a system of equations, and then use a graph to solve.

    Hint:
    A graph is a geometrical representation of an equation or an expression. It can be used to find solutions of equation.
    We are asked to rewrite the equation as system of equations and graph them to solve it.
    Step 1 of 3:
    Equate each side of the equation to a new variable, y:

    Here we get two points where both the graphs intersect each other. The points are (-8, 0) and (-3, -7.5). Thus, we can say that the solutions to the given set of equation are the points of intersection.
     Note:
    When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

    Rewrite the equation as a system of equations, and then use a graph to solve.

    Maths-General

    Hint:
    A graph is a geometrical representation of an equation or an expression. It can be used to find solutions of equation.
    We are asked to rewrite the equation as system of equations and graph them to solve it.
    Step 1 of 3:
    Equate each side of the equation to a new variable, y:

    Here we get two points where both the graphs intersect each other. The points are (-8, 0) and (-3, -7.5). Thus, we can say that the solutions to the given set of equation are the points of intersection.
     Note:
    When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

    Maths-

    Rewrite the equation as a system of equations, and then use a graph to solve.

    Thus, the solutions are (0, 0) and (1, -14)
    Step 3 of 3:
    Plot the points and join them to get the respective graph.

    Here, there is just one point where both the graphs intersect each other. The point is (4, -8). Thus, we can say that the point is the solution of the set of equation.
    Note:
    When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

    Rewrite the equation as a system of equations, and then use a graph to solve.

    Maths-General

    Thus, the solutions are (0, 0) and (1, -14)
    Step 3 of 3:
    Plot the points and join them to get the respective graph.

    Here, there is just one point where both the graphs intersect each other. The point is (4, -8). Thus, we can say that the point is the solution of the set of equation.
    Note:
    When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

    Maths-

    Find the simple interest on Rs. 6500 at 14% per annum for 73 days?

    Complete step by step solution:
    We calculate simple interest by the formula, 
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have 
    On substituting the known values we get, 
    On further simplifications, we have  rupees.
    Thus, SI = 182 Rupees.

    Find the simple interest on Rs. 6500 at 14% per annum for 73 days?

    Maths-General

    Complete step by step solution:
    We calculate simple interest by the formula, 
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have 
    On substituting the known values we get, 
    On further simplifications, we have  rupees.
    Thus, SI = 182 Rupees.

    Maths-

    Rewrite the equation as a system of equations, and then use a graph to solve.

    Here, they graphs intersect at two point; (-1 -1) and (0.5, 2). This means that the solutions of the system of equation are (-1 -1) and (0.5, 2).
    Note:
    Solutions of a set of equation can be found by graphing the equations and finding the intersecting points. The points where they intersect are the solutions.

    Rewrite the equation as a system of equations, and then use a graph to solve.

    Maths-General

    Here, they graphs intersect at two point; (-1 -1) and (0.5, 2). This means that the solutions of the system of equation are (-1 -1) and (0.5, 2).
    Note:
    Solutions of a set of equation can be found by graphing the equations and finding the intersecting points. The points where they intersect are the solutions.

    Maths-

    Rewrite the equation as a system of equations, and then use a graph to solve.

    The required points are: (-1, 4),(1, 4) and (0, 0)
    Step 3 of 3:
    Draw the graph of the set of equations, corresponding to the found points.

    It is clear that there are no points of intersection. Hence, the given equation has no solution.
    Note:
    Maximum solutions possible for a quadratic equation are two. There are instances where the equation has no solutions as well.

    Rewrite the equation as a system of equations, and then use a graph to solve.

    Maths-General

    The required points are: (-1, 4),(1, 4) and (0, 0)
    Step 3 of 3:
    Draw the graph of the set of equations, corresponding to the found points.

    It is clear that there are no points of intersection. Hence, the given equation has no solution.
    Note:
    Maximum solutions possible for a quadratic equation are two. There are instances where the equation has no solutions as well.

    Maths-

    Find the simple interest on Rs. 8000 at 16 % per annum for 9 months?

    Complete step by step solution:
    We calculate simple interest by the formula,  
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have 
    On substituting the known values we get, 
    On further simplifications, we have  rupees.
    Thus, SI = 1000 Rupees.

    Find the simple interest on Rs. 8000 at 16 % per annum for 9 months?

    Maths-General

    Complete step by step solution:
    We calculate simple interest by the formula,  
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have 
    On substituting the known values we get, 
    On further simplifications, we have  rupees.
    Thus, SI = 1000 Rupees.

    Maths-

    The simple interest on a sum of money at the end of 5 years is  of the sum. Find the rate of interest?

    Complete step by step solution:
    Let the sum of money = P
    It is given that  times the sum = 
    We calculate simple interest by the formula, 
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have ,  and R = ?
    On substituting the known values, we have 
    On rearranging the above equation, we get 
    On further simplifications, we get 
    At 16% rate of interest, the simple interest on a sum of money at the end of 5 years is  of sum Itself.

    The simple interest on a sum of money at the end of 5 years is  of the sum. Find the rate of interest?

    Maths-General

    Complete step by step solution:
    Let the sum of money = P
    It is given that  times the sum = 
    We calculate simple interest by the formula, 
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have ,  and R = ?
    On substituting the known values, we have 
    On rearranging the above equation, we get 
    On further simplifications, we get 
    At 16% rate of interest, the simple interest on a sum of money at the end of 5 years is  of sum Itself.

    Maths-

    Find the solution of the system of equations.y = 2x + 5

    Find the solution of the system of equations.y = 2x + 5

    General

    Format the sentence into converts Spanish grammar. "My wife buys a new television for my father”

    Explanation:-
    Because both pronouns "La" and "le" were used in the sentence, the "le" is changed to a "se" in order to fit.

    Format the sentence into converts Spanish grammar. "My wife buys a new television for my father”

    GeneralGeneral

    Explanation:-
    Because both pronouns "La" and "le" were used in the sentence, the "le" is changed to a "se" in order to fit.

    How much will ₹ 5000 amount in 2 years at compound interest if the rate for the successive years are 5% and 4% per year *?

    ∴ Compound Interest =Rs 5724−Rs 5000=Rs 724.

    What will be the compound interest on 5000 in 2 years?

    ∴ Compound interest is Rs.1050 Stay updated with the Quantitative Aptitude questions & answers with Testbook.

    What is the yearly compound amount on Rs 5000 for 2 years at the rate of 10 Pa?

    Answer: So, the compound interest on ₹5000 for 2 years at the rate of 10% is ₹1050 .

    What is the compound interest on rupees 2500 for 2 years at rate of interest 4% per annum?

    = 2704 - 2500 = Rs. 204 C.I. - S.I.