What will be the compound interest on Rupees 9000 at 10% per annum for 2 years 4 months compounded annually?

Compound Interest: The future value (FV) of an investment of present value (PV) dollars earning interest at an annual rate of r compounded m times per year for a period of t years is:

FV = PV(1 + r/m)mtor

FV = PV(1 + i)n

where i = r/m is the interest per compounding period and n = mt is the number of compounding periods.

One may solve for the present value PV to obtain:

PV = FV/(1 + r/m)mt

Numerical Example: For 4-year investment of $20,000 earning 8.5% per year, with interest re-invested each month, the future value is

FV = PV(1 + r/m)mt   = 20,000(1 + 0.085/12)(12)(4)   = $28,065.30

Notice that the interest earned is $28,065.30 - $20,000 = $8,065.30 -- considerably more than the corresponding simple interest.

Effective Interest Rate: If money is invested at an annual rate r, compounded m times per year, the effective interest rate is:

reff = (1 + r/m)m - 1.

This is the interest rate that would give the same yield if compounded only once per year. In this context r is also called the nominal rate, and is often denoted as rnom.

Numerical Example: A CD paying 9.8% compounded monthly has a nominal rate of rnom = 0.098, and an effective rate of:

r eff =(1 + rnom /m)m   =   (1 + 0.098/12)12 - 1   =  0.1025.

Thus, we get an effective interest rate of 10.25%, since the compounding makes the CD paying 9.8% compounded monthly really pay 10.25% interest over the course of the year.

Mortgage Payments Components: Let where P = principal, r = interest rate per period, n = number of periods, k = number of payments, R = monthly payment, and D = debt balance after K payments, then

R = P r / [1 - (1 + r)-n]

and

D = P (1 + r)k - R [(1 + r)k - 1)/r]

Accelerating Mortgage Payments Components: Suppose one decides to pay more than the monthly payment, the question is how many months will it take until the mortgage is paid off? The answer is, the rounded-up, where:

n = log[x / (x � P r)] / log (1 + r)

where Log is the logarithm in any base, say 10, or e.

Future Value (FV) of an Annuity Components: Ler where R = payment, r = rate of interest, and n = number of payments, then

FV = [ R(1 + r)n - 1 ] / r

Future Value for an Increasing Annuity: It is an increasing annuity is an investment that is earning interest, and into which regular payments of a fixed amount are made. Suppose one makes a payment of R at the end of each compounding period into an investment with a present value of PV, paying interest at an annual rate of r compounded m times per year, then the future value after t years will be

FV = PV(1 + i)n + [ R ( (1 + i)n - 1 ) ] / i where i = r/m is the interest paid each period and n = m t is the total number of periods.

Numerical Example: You deposit $100 per month into an account that now contains $5,000 and earns 5% interest per year compounded monthly. After 10 years, the amount of money in the account is:

FV = PV(1 + i)n + [ R(1 + i)n - 1 ] / i =
5,000(1+0.05/12)120 + [100(1+0.05/12)120 - 1 ] / (0.05/12) = $23,763.28

Value of a Bond:

V is the sum of the value of the dividends and the final payment.

You may like to perform some sensitivity analysis for the "what-if" scenarios by entering different numerical value(s), to make your "good" strategic decision.

Replace the existing numerical example, with your own case-information, and then click one the Calculate.

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Let's discuss the concepts related to Interest and Compound Interest. Explore more from Quantitative Aptitude here. Learn now!

Person X borrows Rs 9000 at 10% compound interest. He pays Rs. 2500 at the end of the first year. How much is required for him to pay at end of the second year?

  1. Rs. 7400
  2. Rs. 6750
  3. Rs. 8140
  4. Rs. 4500

Answer (Detailed Solution Below)

Option 3 : Rs. 8140

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Given:

Rate of interest = 10%

Principal amount = 9000

Formula used:

Compound interest: Amount = P (1 + (R/100))n

Where,

n is Number of years,

P is Principal Amount,

R is Rate of Interest,

A is Amount

Calculation:

Calculate amount to be paid at end of year 1

⇒ 9000 × (1 + (10 / 100))

⇒ 9,900

Now, 2500 of this total amount was already paid

⇒ Remaining amount = 9900 – 2500

⇒ Remaining amount = 7400

Now, the final amount to be paid

⇒ 7400 × (1 + (10 / 100))

⇒ 7400 × 1.10

⇒ 8140

 At the end of the second year, person X has to pay Rs. 8140 

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Let's discuss the concepts related to Interest and Compound Interest. Explore more from Quantitative Aptitude here. Learn now!

What is the compound interest on 10000 for 2 years at 10% per annum?

Compound Interest would be 12100rs.

What is the compound interest on 12000 rs at the rate of 10% for 2 years?

Hence, the compound interest is Rs. 2,520.

What is the compound interest on rupees 20000 at 10% for 2 years?

Where P is principal, R is rate of interest and T is time. ∴ The compound interest for 2 years is Rs. 2464.

What is the compound interest on rupees 10000 at 10% for 3 years?

=13310–10000=₹ 3310.