 Show 1) k ≤ 0 2) k ≥ 0 3) 0 ≤ k ≤ 1 / 4 4) 0 ≤ k ≤ 1 Solution: (3) 0 ≤ k ≤ 1 / 4 m1m2 ≤ 1 k . 4 ≤ 1 k ≤ 1 / 4 Also, m1 and m2 must be of the same sign. k ≥ 0 Hence 0 ≤ k ≤ 1 / 4 Was this answer helpful? 0 (0) (1) (2) Choose An Option That Best Describes Your ProblemAnswer not in Detail Incomplete Answer Answer Incorrect Others Answer not in Detail Incomplete Answer Answer Incorrect Others Thank you. Your Feedback will Help us Serve you better. Leave a CommentYour Mobile number and Email id will not be published.
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* * if x is equal to 4 Y + fine and where is Dukh Express Pora the lines of regression or nationwide and Y on X respectively where is positive constant prove that it can take one line of regression of Y on X is given by Y is equal to X + 10 the line of origin of x on Y given by x is equal to four ok sunao general equation of a lower end of line of regression of Y on X is given by Y minus Y is equal to X 2 x minus 2 equations that Y is equal to b y x y x x we can say that the value of Y is equal to the equation of line of regression of X and Y is given by x minus 6 is equal to b h u x x minus y again comparing the equation we can say that the value of x is equal to four ok sunao relation which is the product of V X Y and Z to put in the values we can say that ok is equal to cannot take need one cause I always like between -1 and 1 question we can say that focus on to be less than equal to 1 Given equations of regression lines are x - 4y = 5 …(i) 16y - x = 64 i.e., - x + 16y = 64 …(ii) Adding (i) and (ii), we get x - 4y = 5 ∴ y = `69/12 = 5.75` Substituting y = 5.75 in (i), we get x - 4(5.75) = 5 ∴ x - 23 = 5 ∴ x = 5 + 23 = 28 Since the point of intersection of two regression lines is `(bar x, bar y)`, ∴ `bar x = 28 and bar y = 5.75` Let, x - 4y = 5 be the regression equation of X on Y ∴ The equation becomes X = 4Y + 5 Comparing it with X = bXY Y + a', we get bXY = 4 Now, the other equation i.e. 16y - x = 64 is regression equation of Y on X ∴ The equation becomes 16Y = X + 64 i.e., Y = `1/16 "X" + 64/16` Comparing it with Y = bYX X + a, we get `"b"_"YX" = 1/16` r = `+-sqrt("b"_"XY" * "b"_"YX")` `= +- sqrt(4 xx 1/16) = +- sqrt(1/4) = +- 1/2 = +- 0.5` Since bXY and bYX both are positive, r is also positive. ∴ r = 0.5 How do you find the regression coefficient of X on Y?The regression equation X on Y is X = c + dy is used to estimate value of X when Y is given and a, b, c and d are constant. Y = a + bx can also be interpreted as 'a' is the average value of Y when X is zero. X = c + dy, value c is the average value of X, when Y is zero.
What is the regression coefficient for X?The regression coefficient of y on x is denoted by byx. The regression coefficient of x on y is denoted by bxy. 4.
Is regression X on Y or Y on X?If y represents the dependent variable and x the independent variable, this relationship is described as the regression of y on x. The relationship can be represented by a simple equation called the regression equation.
What are the regression lines and coefficients of x and y variables?Regression Coefficient
The two constants a and b are regression parameters. Furthermore, we denote the variable b as byx and we term it as regression coefficient of y on x. Also, we can have one more definition for the regression line of y on x. We can call it the best fit as the result comes from least squares.
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If the regression line of x on y is x - 4y = 5 then the regression coefficient of x on y is
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